H(t)=-16t^2+96t+64

Solution for H(t)=-16t^2+96t+64 equation:

(H)=-16H^2+96H+64

We move all terms to the left:

(H)-(-16H^2+96H+64)=0

We get rid of parentheses

16H^2-96H+H-64=0

We add all the numbers together, and all the variables

16H^2-95H-64=0

a = 16; b = -95; c = -64;
Δ = b2-4ac
Δ = -952-4·16·(-64)
Δ = 13121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-95)-\sqrt{13121}}{2*16}=\frac{95-\sqrt{13121}}{32}
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-95)+\sqrt{13121}}{2*16}=\frac{95+\sqrt{13121}}{32}
$